🖐 Blackjack Odds Better with More Players? - Bodog Casino Blog

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Blackjack - Multiple Hands / Players - Wizard of Odds
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The Effects of Number of Decks on House Edge
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Blackjack Betting Tips With A REAL DEALER! - Diamond Casino Odds - GTA 5 Online

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Learn more about Blackjack Odds & Probability, the House Edge and the Free Spins credited once deposit amount has been wagered. Even though the dealer has a huge advantage by always acting last, we players do after all have a lot of Please note that the probability for this varies depending on what the rules.


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The Maths Behind Blackjack

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No Bust Blackjack Strategy: Does it Work?

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How to Count Cards (and Bring Down the House)

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The Wizard of Odds answers readers' questions about Blackjack. Do you change your strategy based on the play of other players at your table? As I have said many times, the more ridiculous a belief is, the more tenaciously it tends to be.


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Why do blackjack simulators and blackjack authors state that the odds for a (2) I don't have to simulate this because the number of players makes no difference. If there were a shuffle between hands the probability would increase.


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How to win at blackjack (21) with gambling expert Michael \

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A Guide to Advantage Play in Blackjack - Blackjack for Advanced Players

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Players can make larger bets when they have an advantage. For example, the players can increase the starting bet if there are many aces and tens left in the deck.


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Blackjack Expert Explains How Card Counting Works - WIRED

What is important is that you play your cards right. As I always say all betting systems are equally worthless so flying by the seat of your pants is just as good as flat betting over the long term. For the non-card counter it may be assumed that the odds are the same in each new round. Probability of Blackjack Decks Probability 1 4. From my section on the house edge we find the standard deviation in blackjack to be 1. I would have to do a computer simulation to consider all the other combinations. Thanks for your kind words. So the probability of winning six in a row is 0. Expected Values for 3-card 16 Vs. There are cards remaining in the two decks and 32 are tens. My question though is what does that really mean? I know, I know, its some sort of divine intervention betting system I am talking about and no betting system affects the house edge. To test the most likely case to favor hitting, 8 decks and only 3 cards, I ran every possible situation through my combinatorial program. For each rank determine the probability of that rank, given that the probability of another 8 is zero. Besides every once in awhile throwing down a bigger bet just adds to the excitement and for some reason it seems logical that if you have lost a string of hands you are "due" for a win. For how to solve the problem yourself, see my MathProblems. Streaks, such as the dealer drawing a 5 to a 16, are inevitable but not predictable. All of this assumes flat betting, otherwise the math really gets messy. What you have experienced is likely the result of some very bad losing streaks. Your question however could be rephrased as, "what is the value of the ace, given that the other card is not a ten. Is it that when I sit down at the table, 1 out of my next playing sessions I can expect to have an 8 hand losing streak? If there were a shuffle between hands the probability would increase substantially. Repeat step 3 but multiply by 3 instead of 2. However if you were going to cheat it would be much better to remove an ace, which increases the house edge by 0. This is not even a marginal play. If you want to deviate from the basic strategy here are some borderline plays: 12 against 3, 12 against 4, 13 against 2, 16 against Deviating on these hands will cost you much less. So, the best card for the player is the ace and the best for the dealer is the 5. The best play for a billion hands is the best play for one hand. When the dealer stands on a soft 17, the dealer will bust about When the dealer hits on a soft 17, the dealer will bust about According to my blackjack appendix 4 , the probability of a net win is However, if we skip ties, the probability is So, the probability of a four wins in a row is 0. Multiply dot product from step 11 by probability in step 9. The probability of this is 1 in 5,,, For the probability for any number of throws from 1 to , please see my craps survival tables. It depends whether there is a shuffle between the blackjacks. In that case, the probability of a win, given a resolved bet, is The probability of winning n hands is a row is 0. According to my blackjack appendix 9H the expected return of standing is So my hitting you will save 6. I hope this answers your question. I have a very ugly subroutine full of long formulas I determine using probability trees.{/INSERTKEYS}{/PARAGRAPH} That column seemed to put the mathematics to that "feeling" a player can get. Because the sum of a large number of random variables always will approach a bell curve we can use the central limit theorem to get at the answer. Thanks for the kind words. You ask a good question for which there is no firm answer. Or does it mean that on any given loss it is a 1 in chance that it was the first of 8 losses coming my way? Following this rule will result in an extra unit once every hands. Determine the probability that the player will not get a third eight on either hand. It would take about 5 years playing blackjack 40 hours a week before this piece of advice saved the player one unit. Resplitting up to four hands is allowed. The standard deviation of one hand is 1. {PARAGRAPH}{INSERTKEYS}This is a typical question one might encounter in an introductory statistics class. However there are other ways you get four aces in the same hand, for example the last card might be an 8 or 9. If you were to add a card as the dealer you should add a 5, which increases the house edge by 0. Take the dot product of the probability and expected value over each rank. In general the variation in the mean is inversely proportional to the square root of the number of hands you play. I have no problem with increasing your bet when you get a lucky feeling. Add values from steps 4, 8, and The hardest part of all this is step 3. It may also be the result of progressive betting or mistakes in strategy. Repeat step 3 but multiply by 4 instead of 2, and this time consider getting an 8 as a third card, corresponding to the situation where the player is forced to stop resplitting. The following table displays the results. It took me years to get the splitting pairs correct myself. There are 24 sevens in the shoe. Let n be the number of decks. Blackjack is not entirely a game of independent trials like roulette, but the deck is not predisposed to run in streaks. I recently replaced my blackjack appendix 4 with some information about the standard deviation which may help. So standing is the marginally better play. From my blackjack appendix 7 we see that each 9 removed from a single deck game increases the house edge by 0. You are forgetting that there are two possible orders, either the ace or the ten can be first. Take another 8 out of the deck. These expected values consider all the numerous ways the hand can play out. Putting aside some minor effects of deck composition, the dealer who pulled a 5 to a 16 the last five times in a row would be just as likely to do it the next time as the dealer who had been busting on 16 for several hours. When I said the probability of losing 8 hands in a row is 1 in I meant that starting with the next hand the probability of losing 8 in a row is 1 in The chances of 8 losses in a row over a session are greater the longer the session. The fewer the decks and the greater the number of cards the more this is true. Cindy of Gambling Tools was very helpful. Unless you are counting cards you have the free will to bet as much as you want. Steve from Phoenix, AZ. Here is the exact answer for various numbers of decks. Determine the probability that the player will resplit to 4 hands. Multiply this dot product by the probability from step 2. It depends on the number of decks. There is no sound bite answer to explain why you should hit. It is more a matter of degree, the more you play the more your results will approach the house edge. According to my blackjack appendix 4 , the probability of an overall win in blackjack is I'm going to assume you wish to ignore ties for purposes of the streak. Any basic statistics book should have a standard normal table which will give the Z statistic of 0. If I'm playing for fun then I leave the table when I'm not having fun any longer. Here is how I did it. Determine the probability that the player will resplit to 3 hands. Multiply dot product from step 7 by probability in step 5. Since this question was submitted, a player held the dice for rolls on May 23, in Atlantic City. Go through all ranks, except 8, subtract that card from the deck, play out a hand with that card and an 8, determine the expected value, and multiply by 2. If the probability of a blackjack is p then the probability of not getting any blackjacks in 10 hands is 1- 1-p For example in a six deck game the answer would be 1- 0.